Working on MAT-204 - Good Progress

fall-2024/math/mat-203/00020/.~lock.mat-203-00020.odt#

@@ -1 +0,0 @@
-,slimbook,wins-slimbook,23.11.2024 10:25,file:///home/slimbook/.var/app/org.libreoffice.LibreOffice/config/libreoffice/4;

fall-2024/math/mat-204/00010/.~lock.mat-204-00010 - probability.odt#

@@ -0,0 +1 @@
+,winsdominoes,fedora,23.11.2024 20:14,file:///home/winsdominoes/.var/app/org.libreoffice.LibreOffice/config/libreoffice/4;

fall-2024/math/mat-204/00010/.~lock.mat-204-00020 - probability.odt#

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-,slimbook,wins-slimbook,23.11.2024 10:26,file:///home/slimbook/.var/app/org.libreoffice.LibreOffice/config/libreoffice/4;

fall-2024/math/mat-204/Game.ipynb

@@ -1,8 +1,23 @@
 {
  "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# MAT-204:00010 - Probability\n",
+    "Author: Thanawin Pattanaphol - Date: 23th December 2024 - Description: Basic probability calculations"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Importing Libraries"
+   ]
+  },
   {
    "cell_type": "code",
-   "execution_count": 50,
+   "execution_count": null,
    "metadata": {},
    "outputs": [],
    "source": [
@@ -12,12 +27,26 @@
     "\n",
     "Dat = pd.read_csv('DataLoL.csv')\n",
     "\n",
-    "nGame = len(Dat)"
+    "num_games = len(Dat)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Questions"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team wins"
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 51,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -29,13 +58,23 @@
     }
    ],
    "source": [
-    "ProbBlueWins = len(Dat[Dat['blueWins'] == 1]) / nGame\n",
+    "# Calculating the probability by diving the amount of games that blue won\n",
-    "print(\"Probability that Blue Team wins is: \", ProbBlueWins)"
+    "# dividing it by the amount of total games\n",
+    "# Thus: p = Number of time an event occurs / Total nmumber of possible events\n",
+    "prob_blue_wins = len(Dat[Dat['blueWins'] == 1]) / num_games\n",
+    "print(\"Probability that Blue Team wins:\", prob_blue_wins)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team wins and kills the dragon"
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 52,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -47,13 +86,24 @@
     }
    ],
    "source": [
-    "ProbBlueWinsAndDragon = len(Dat[(Dat['blueWins'] == 1) & (Dat['blueDragons'] == 1)]) / nGame\n",
+    "# Doing a similar calculation with the difference being\n",
-    "print(\"Probability that Blue Team wins and kills the dragon is: \", ProbBlueWinsAndDragon)"
+    "# the number of time an event occurs now only counts\n",
+    "# the number of times blue team wins and kills the dragon\n",
+    "\n",
+    "prob_blue_wins_dragons = len(Dat[(Dat['blueWins'] == 1) & (Dat['blueDragons'] == 1)]) / num_games\n",
+    "print(\"Probability that Blue Team wins and kills the dragon:\", prob_blue_wins_dragons)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team wins and kills the herald"
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 53,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -65,13 +115,23 @@
     }
    ],
    "source": [
-    "ProbBlueWinsAndHerald = len(Dat[(Dat['blueWins'] == 1) & (Dat['blueHeralds'] == 1)]) / nGame\n",
+    "# Similar calculation but with the number of events that\n",
-    "print(\"Probability that Blue Team wins and kills the herald is: \", ProbBlueWinsAndHerald)"
+    "# team blue wins and kills the herald\n",
+    "\n",
+    "prob_blue_wins_heralds = len(Dat[(Dat['blueWins'] == 1) & (Dat['blueHeralds'] == 1)]) / num_games\n",
+    "print(\"Probability that Blue Team wins and kills the herald:\", prob_blue_wins_heralds)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Count: All possible cases (Venn Diagram)"
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 54,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -86,16 +146,19 @@
     }
    ],
    "source": [
-    "game_blue_wins = set()\n",
+    "# Declaring variable for each set\n",
-    "game_blue_dragon = set()\n",
+    "# Loop through the whole games dataset and if the item-\n",
-    "game_blue_herald = set()\n",
+    "# -matches the condition, add it to the set for that\n",
+    "# condition list\n",
     "\n",
-    "for game in range(nGame):\n",
+    "game_blue_wins, game_blue_dragon, game_blue_herald = set()\n",
+    "\n",
+    "for game in range(num_games):\n",
     "    if(Dat['blueWins'][game] == 1):\n",
     "        game_blue_wins.add(game)\n",
-    "    if(Dat['blueDragons'][game] == 1):\n",
+    "    else if(Dat['blueDragons'][game] == 1):\n",
     "        game_blue_dragon.add(game)\n",
-    "    if(Dat['blueHeralds'][game] == 1):\n",
+    "    else if(Dat['blueHeralds'][game] == 1):\n",
     "        game_blue_herald.add(game)\n",
     "\n",
     "venn3([game_blue_wins, game_blue_dragon, game_blue_herald], ('A', 'B', 'C'))\n",
@@ -103,9 +166,16 @@
     "plt.show()"
    ]
   },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Each possible events (Venn Diagram)"
+   ]
+  },
   {
    "cell_type": "code",
-   "execution_count": 55,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -120,6 +190,11 @@
     }
    ],
    "source": [
+    "# Setting the variable for each section of the venn diagram\n",
+    "# Use these values to calculate its probability by\n",
+    "# diving with the total amount of games\n",
+    "# Produce venn diagram of the values\n",
+    "\n",
     "count_a = 2055\n",
     "count_b = 1096\n",
     "count_c = 564\n",
@@ -130,22 +205,29 @@
     "\n",
     "count_abc = 522\n",
     "\n",
-    "p_a = round(2055 / nGame, 3)\n",
+    "p_a = round(2055 / num_games, 3)\n",
-    "p_b = round(1096 / nGame, 3)\n",
+    "p_b = round(1096 / num_games, 3)\n",
-    "p_c = round(564 / nGame, 3)\n",
+    "p_c = round(564 / num_games, 3)\n",
     "\n",
-    "p_ab = round(1770 / nGame, 3)\n",
+    "p_ab = round(1770 / num_games, 3)\n",
-    "p_ac = round(583 / nGame, 3)\n",
+    "p_ac = round(583 / num_games, 3)\n",
-    "p_bc = round(188 / nGame, 3)\n",
+    "p_bc = round(188 / num_games, 3)\n",
     "\n",
-    "p_abc = round(522 / nGame, 3)\n",
+    "p_abc = round(522 / num_games, 3)\n",
     "\n",
     "venn = venn3(subsets=(p_a, p_b, p_ab, p_c, p_ac, p_bc, p_abc), set_labels=('A', 'B', 'C'))"
    ]
   },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team does not manage to do any of the events (Outer White Section)"
+   ]
+  },
   {
    "cell_type": "code",
-   "execution_count": 56,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -157,12 +239,25 @@
     }
    ],
    "source": [
-    "print(\"Probabilty that Blue Team loses, doesn't kill dragons and heralds: \", (nGame - (count_a + count_b + count_c + count_ab + count_abc + count_ac + count_bc)) / nGame)"
+    "# Calculate the total amount of the games in the venn diagram\n",
+    "# Find the complement of (A ∪ B ∪ C)\n",
+    "\n",
+    "count_all = count_a + count_b + count_c + count_ab + count_abc + count_ac + count_bc\n",
+    "did_not_win_all = num_games - p_all_wins\n",
+    "\n",
+    "print(\"Probabilty that Blue Team loses, doesn't kill dragons and heralds:\", did_not_win_all / num_games)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team wins and kills dragon and herald"
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 57,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -174,12 +269,22 @@
     }
    ],
    "source": [
-    "print(\"Probability that blue team wins, kills dragon and herald: \", p_abc)"
+    "# The probability of this event is essentially the intersection of\n",
+    "# A (Blue Team Wins), B (Kills Dragon) and C (Kills Herald)\n",
+    "\n",
+    "print(\"Probability that blue team wins, kills dragon and herald:\", p_abc)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team does not win but kills dragon and the herald "
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 58,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -191,12 +296,22 @@
     }
    ],
    "source": [
-    "print(\"Probability that blue team kills dragon and the herald but does not win: \", p_bc)"
+    "# Same with above but only with the intersection between\n",
+    "# B (Kills Dragon) and C (Kills Herald)\n",
+    "\n",
+    "print(\"Probability that blue team does not win but kills dragon and the herald :\", p_bc)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "#### Probability: Blue Team wins but does not kill dragon and herald. "
    ]
   },
   {
    "cell_type": "code",
-   "execution_count": 59,
+   "execution_count": null,
    "metadata": {},
    "outputs": [
     {
@@ -208,7 +323,9 @@
     }
    ],
    "source": [
-    "print(\"Probability that blue team wins without killing the graon and the herald: \", p_a)"
+    "# Same with above but only with the A section (Blue Team wins)\n",
+    "\n",
+    "print(\"Probability that blue team wins without killing the dragon and the herald:\", p_a)"
    ]
   }
  ],
@@ -228,7 +345,7 @@
    "name": "python",
    "nbconvert_exporter": "python",
    "pygments_lexer": "ipython3",
-   "version": "3.12.6"
+   "version": "3.11.2"
   }
  },
  "nbformat": 4,